If you have SPSS here are some ways to do this.

the squared Euclidean distance is the sum of the squared distances on each dimension.
If you have 10 z variables  try something like this untested syntax. which will find the distance of each case from each centroid.
create 60 variables for the centroids in a file with 1 "case" with a variable called constant  set to 1, and 6 sets of  10 
cen1z1 to cen1z10 cen2z1 to cen2z10 ...cen6z1 to cen6z10

in your main file
compute constant=1.
match files file=main /table= centroids by constant.

do repeat
vector
   distance= distance1 to distance6
/ z = z1 to z10
/ center1 = cen1z1 to cen1z10
 / center2 = cen2z1 to cen2z10
. . .
 / center6 = cen6z1 to cen6z10.

loop #i =1 to 6
compute distance(#i)=0.
loop #j = 1 to 10.
distance (#i) = distance(#i)  + ((center(#i) - z(#j)**2).
end loop.
end loop.


If you do not have a huge number of cases and have a fairly powerful machine a solution with less effort on your part but a lot of computation for the machine  might be this.
Just add 6 cases to the main each representing a centroid at the top of the files and do PROXIMITIES on the large matrix and then delete the columns you do not want.

Another way to look at the agreement between two solutions is to do the clusterings with filtered cases saving the memberships.
Then do two DISCRIMINANTs, each time treating the other set of cases as unclustered in the classification phase saving the assignments and probabilities of membership on each pass.
Then CROSSTAB the assignments on the DFA with those from the original clustering.

Art Kendall
Social Research Consultants




Liza Rovniak wrote:
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Hi,

 

I am hoping someone here can help me with a “how to” question on running McIntyre and Blashfield’s (1980) nearest-centroid evaluation procedure to validate the stability of my cluster analysis solution. I am a newbie to cluster analysis, so this is my first time running this procedure.

 

I have a sample of  about 900 observations and have randomly split the sample in two (Sample A and Sample B). I conducted hierarchical cluster analysis and then calculated the centroid vectors for a 3-cluster solution on each of these two subsamples (i.e., steps 1 through 4 of McIntrye and Blashfield’s evaluation technique).

 

Step 5 of McIntrye and Blashfield’s technique is to calculate “the squared Euclidean distance for each of Sample B’s objects from each of the centroids of Sample A,” and Step 6 is to assign “each object  in Sample B to the closest centroid vector.” At this point, I am not sure what buttons to press in SPSS to complete the analysis. One possibility I tried is to use K-means cluster analysis to achieve these two steps, but K-means uses simple Euclidean distance (not squared Euclidean distance as recommended by McIntyre and Blashfield) to assign the observations to clusters. Is this okay? (someone told me it was, but I just want to double-check).  I would greatly appreciate any guidance on what buttons to press in SPSS/appropriate syntax to complete steps 5 and 6 of this analysis.

 

Thank you.

 

Liza Rovniak

 

Liza S. Rovniak, PhD, MPH

Adjunct Assistant Professor

Center for Behavioral Epidemiology & Community Health

Graduate School of Public Health, San Diego State University

San Diego, CA 92123

Phone: 858-505-4770, ext. 152; Fax: 858-505-8614

Email: [log in to unmask]

 

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